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If p is the point of contact of thecircles x^2 + y^2 + 4x + 4y - 10 = 0and x^2 + y^2 - 6x - 6y + 10 = 0and Q is theirexternal centre of similitude, then the equation of the circle with P and Q as the extremities of its diameter is |
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Answer» `x^2 + y^2 + 14X + 14y - 26 = 0` |
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