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    				| 1. | If P{X = 0} = 1 – P{X = 1}. If E[X] = 3Var(X), then P{X = 0}.(a) 2/3(b) 2/5(c) 1/5(d) 1/3 | 
| Answer» (d) 1/3 Given P (X = 0) = 1 – P (X = 1) ⇒ P (X = 1) = 1 – P (X = 0) Let n = P(X = 0), ∴ P(X = 1) = 1 - n E(X) = (0) (n) + (1) (1 – n) = 1 – n E(X2) = (0)2 (n) + (1)2 (1 – n) = 1 – n Now substituting E(X) = 3 Var (X), we get n = (1/3) (or) 1 ∴ P(X = 0 ) = 1/3 | |