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If $p x^{2}+3 x+q=0$ has two roots $x=-1$ and $x=-2,$ find $p-q$ |
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Answer» x=-1so p-3+q=0so p+q=3x=-24p-6+q=94p+q=64p+q-p-q=6-3=3so 3p=3 so p=1so q=2so p-q=1-2=-1 |
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