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If p(x) is a cubic polynomial with p(1)=3, p(0)=2, p(−1)=4, then 1∫−1p(x)dx is |
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Answer» If p(x) is a cubic polynomial with p(1)=3, p(0)=2, p(−1)=4, then 1∫−1p(x)dx is |
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