If pH of a saturated solution of Ba(OH)_2 is 12, the value of its K_((

1.	If pH of a saturated solution of Ba(OH)_2 is 12, the value of its K_((Sp)) is :
Answer» `4.0xx10^(-6) M^3` `4.0xx10^(-7)M^3` `5.0xx10^(-6) M^3` `5.0xx10^(-7) M^3` Solution :`BA(OH)_(2(s)) to Ba_((aq))^(+2) + 2OH_((aq))^(-)` pH=12 or pOH=2 `[OH^-]=10^(-2)` M `{:(Ba(OH)_2 to , Ba^(+2)+, 2OH^-),(,0.5xx10^(-2), 10^(-2)):}` [`because` CONCENTRATION of `Ba^(2+)` is half of `OH^-` ] `K_(sp)= [Ba^(+2)][OH^-]^2` `=[0.5xx10^(-2)][1.0xx10^(-2)]^2` `=0.5xx10^(-6)=5.0xx10^(-7) M^3`

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