1.

If pH of a saturated solution of `Ba(OH)_(2)` is 12, the value of its `K_((sp))` isA. `5.00 xx 10^(-7) M^(3)`B. `4.00 xx 10^(-6) M^(3)`C. `4.00 xx 10^(-7) M^(3)`D. `5.00 xx 10^(-6) M^(3)`

Answer» Correct Answer - A
pH = 12 means `[H^(+)]=10^(-12)M`.
Hence, `[OH^(-)]=10^(-2)M`
`Ba(OH)_(2) hArr Ba^(2+)+2OH^(-)`
`[OH^(-)]=10^(-2)M`
`:. Ba^(2+)=(10^(-2))/(2) M=5xx10^(-3)M`
`K_(sp)=[Ba^(2+)][OH^(-)]^(2)`
`=(5xx10^(-3))(10^(-2))^(2)=5xx10^(-7) M^(3)`


Discussion

No Comment Found

Related InterviewSolutions