1.

If (pi)/(2) lt alpha (3pi)/(2) , the modulus argument form of (1 + cos 2 alpha) + isin 2 alpha is

Answer»

`-2COS ALPHA{COS(alpha-pi)+ISIN(alpha-pi)}`
`2cos alpha{cos(alpha)+isinalpha)`
`2cos alpha{cos(-alpha)+isin(-alpha)}`
`-2cos alpha{cos(pi-alpha)+isin(pi-alpha)}`

ANSWER :A


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