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If plane 2x+3y+6z+k=0 is tangent to the sphere x^(2)+y^(2)+z^(2)+2x-2y+2z-6=0, then a value of k is |
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Answer» 26 Distance of `(-1,1,-1)` from the plane is `|(-2+3-6+k)/SQRT(4+9+36)|`. Since, the plane is TANGENT to the plane. `therefore |(k-5)/7|=3`. `therefore k=-16,26` |
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