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If Plank constant (h) speed of free space light (c) and Newton gravitation constant (G) are chosen as the fundamental quantities, then dimensional formula of length will be ...... |
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Answer» `sqrt((hc)/(G))` `:. l=kh^(a)G^(b)c^(d)` `M^(0)L^(1)T^(0)=(M^(2)L^(2)T^(-1))^(a)(M^(-1)L^(3)T^(-2))^(b) (M^(0)L^(1)T^(-1))^(d)` `=M^(a-b)L^(2a+3b+d) T^(-a-2b-d)` `a-b=0 "" ...(1)` `2a+3b+d=1 "" ...(2)` `-a-2b-d=0 ""...(3)` `:.` From equation (2) and (3) `5b+d=1 "" ...(4)` and `-3b-d=0 "" ...(5)` Add by equation (4) and (5) `2b=1` `:.b=(1)/(2) "" :. a=(1)/(2)` From equation (3) `:.-d=a+2b=(1)/(2)+1=(3)/(2)` `:.d=-(3)/(2)` `l=h^((1)/(2))G^((1)/(2))c^(-(3)/(2))` `:.l=((hG)^((1)/(2)))/(c^((3)/(2)))` `= (sqrt(hG))/(c^((3)/(2)))` |
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