If potential energy due to attractive force in circular path of radius r is U=-k/(2r^2), then its total energy = …... .

If potential energy due to attractive force in circular path of radius

1.	If potential energy due to attractive force in circular path of radius r is U=-k/(2r^2), then its total energy = …... .
Answer» ANSWER :zero `U=-k/(2r^2)RARR(dU)/(dr)=+k/R^3` `:.F=k/r^3` But for circular motion, centipetal force `F=(mv^2)/r` `:.(mv^2)/r=k/r^3` `:. 1/2mv^2=k/(2r^2)` `:. K=k/(2r^2)` `:.` Total ENERGY `E=U+K=-k/(2r^2)+k/(2r^2)=0`