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If power dissipated in the `9 Omega` resistor in the resistor shown is `36 W`, the potential difference across the `2 Omega` resistor is A. 8VB. 10VC. 2VD. 4V |
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Answer» Correct Answer - B Electric power, `P = i^(2)R` `therefore " "` Current, `I = sqrt((P)/(R ))` For resistance of 9 `Sigma`, `i_(1)=sqrt((36)/(9))=sqrt(4)=2A` `i_(2)=(i_(1)xxR)/(6)=(2xx9)/(6)=3A` `i=i_(1)+i_(2)=2+3=5A` `V_(2)=lR_(2)=5xx2=10V` |
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