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If power dissipated in the `9 Omega` resistor in the resistor shown is `36 W`, the potential difference across the `2 Omega` resistor is A. `8 V`B. `10 V`C. `2 V`D. `4 V` |
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Answer» Correct Answer - B (b) Electric power, `p = i^(2) R` `:.` Current, `I = sqrt((p)/(R ))` Fro resistance of `9 Omega` `i_(1) = sqrt((36)/(9)) = sqrt4 = 2 A` `i_(2) = (i_(1) xx R)/(6) = (2 xx 9)/(6) = 3 A` `i- i_(1) + i_(2) = 2 + 3 = 5A` `V_(2) = IR_(2) = 5 xx 2 = 10 V` |
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