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If pressure of a gas contained in a closed vessel is increased by 0.4% when heated by 1°C fts initial temperature must be-(A) 250K(B) 250°c(C) 2500K(D) 25°C

Answer»

Let P2 = 1.004 P1 ..... A 0.4% increase in PLet T2 = T1 + 1 ........... See note below

P1V1/T1 = P2V2/T2 ..... combined gas lawP1/T1 = P2/T2 ............... Assume V remains constant.T1 = P1T2 / P2 .............. solve for T1T1 = P1(T1+1) / (1.004P1)T1 = (T1+1) / 1.0041.004T1 = T1 + 11.004T1 - T1 = 10.004T1 = 1T1 = 1 / 0.004T1 = 250KA 1 degree increase on the Celsius scale is a 1 degree increase on the Kelvin scale. Temperatures used in the combined gas law must be in Kelvin



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