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If pth, qth , rth and sth terms of an AP are in GP then show that (p-q), (q-r), (r-s) are also in GPA. A.PB. G.PC. H.PD. none of these |
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Answer» Correct Answer - B Given that a+(p-1)d=A a+(q-1)d=AR `a+(r-1)d=AR^(2)` `a+(s-1)d=AR^(3)` where R is common ratio of G.P. Now, `p-q=(A-AR)/d,q-r=R((A-AR)/d)` Clearly,p-q,q-r,r-s are in G.P. |
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