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{ If }∑_{r=0}^{2n}a_r(x-2)^r=∑_{r=0}^{2n}b_r(x-3)^r and }a_k=1,∀ k≥ n, then }} show that }b_n=^{2n+1}C_{n+1 |
| Answer» { If }∑_{r=0}^{2n}a_r(x-2)^r=∑_{r=0}^{2n}b_r(x-3)^r and }a_k=1,∀ k≥ n, then }} show that }b_n=^{2n+1}C_{n+1 | |