If r=0.997,sumxy=46,bar(X)=4,bar(Y)=8,sumx^(2)=28, what will be the value of sumy^(2)?

If r=0.997,sumxy=46,bar(X)=4,bar(Y)=8,sumx^(2)=28, what will be the va

1.	If r=0.997,sumxy=46,bar(X)=4,bar(Y)=8,sumx^(2)=28, what will be the value of sumy^(2)?
Answer» <html><body><p></p>Solution :`r=(sumxy)/(sqrt(sumx^(2)xxsumy^(2)))` <br/> Given : `r=0.997, sum xyl =<a href="https://interviewquestions.tuteehub.com/tag/46-317673" style="font-weight:bold;" target="_blank" title="Click to know more about 46">46</a> , bar (X)=<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>,bar (Y)=8, sum x^(2)=28` <br/> Substituting the <a href="https://interviewquestions.tuteehub.com/tag/values-25920" style="font-weight:bold;" target="_blank" title="Click to know more about VALUES">VALUES</a>,we get <br/> `0.997=(46)/(sqrt(28xx <a href="https://interviewquestions.tuteehub.com/tag/sumy-2258423" style="font-weight:bold;" target="_blank" title="Click to know more about SUMY">SUMY</a>^(2)))` <br/> Squaring both <a href="https://interviewquestions.tuteehub.com/tag/side-1206832" style="font-weight:bold;" target="_blank" title="Click to know more about SIDE">SIDE</a> , we get <br/> `0.994=(2,116)/(28xxsumy^(2))` <br/> `implies 27.832xx sumy^(2)=2,116` <br/> `sumy^(2)=76.03` <br/> Value of `sumy^(2)=76.03`</body></html>