If r.m.s. speed of gaseous molecules is x cm/sec at a pressure of p atm r.m.s. at a pressure of 2p atm and constant temperature will be

If r.m.s. speed of gaseous molecules is x cm/sec at a pressure of p at

1.	If r.m.s. speed of gaseous molecules is x cm/sec at a pressure of p atm r.m.s. at a pressure of 2p atm and constant temperature will be
Answer» x 2x 4x x/4 Solution :`u=SQRT((3RT)/(M))=sqrt((3PV)/(M))`. As TEMPERATURE is constant, Pv is constant. Hence, r.m.s. is constant even if pressure is doulbed. Alternatively, `u=sqrt((3P)/(d))`. At constant TEMP. , if P is doulbed, d is doubled so that u remians same.