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If `r^[th]` and `(r+1)^[th]` term in the expansion of `(p+q)^n` are equal, then `[(n+1)q]/[r(p+q)]` isA. `(1)/(2)`B. `(1)/(4)`C. `1`D. `0` |
Answer» Correct Answer - C `(c )` `T_(r )=^(n)C_(r-1)p^(n-r+1)*q^(r-1)` `=T_(r+1)=^(n)C_(r)p^(n-r)*q^(r )` (given) `impliesp^(n-r+1)*q^(r-1)=(n-r+1)/(r )p^(n-r)*q^(r )` `implies(p)/((n-r+1))=(q)/(r )` `implies((n+1)q)/((p+q)r)=1` |
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