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If ratio of area enclosed in `6^(th)` orbit in H atom to 2nd orbit in `Li^(+2)` ion is `3^(x)` then find the value of x ? |
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Answer» Correct Answer - 1 `2C(s)+O_(2)(g)iff2CO(g),K_(2)` `CO_(2)(g)iffC(s)+O_(2)(g),1//K_(1)` `C(s)+CO_(2)(g)iff2CO(g),K_(3)` `K_(3)=(K_(2))/(K_(1))=(10^(-3))/(10^(-2))=10^(-1)` `C(s)+O_(2)(g)iffCO_(2)(g), K_(1)` `2CO(g)iffC(s)+CO_(2)(g)" "1//K_(3)` `2CO(g)+O_(2)(g)iff2CO_(2)(g), K_(4)` `K_(4)=(K_(1))/(K_(3))=(10^(-2))/(10^(-1))=10^(-1)` `(x)/(y)=1` |
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