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if `rho` is the density of the meterial of a wire and `sigma` is the breaking stress. The greatest length of the wire that can hang freely without breaking isA. `(2sigma)/(rhog)`B. `(rho)/(sigmag)`C. `(rhog)/(2sigma)`D. `(sigma)/(rhog)` |
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Answer» Correct Answer - D Maximum stress on the wire will be at highest point (at the point of suspension) `thereforestress=("weight")/(A)=(Alrhog)/(A)=sigma` `thereforel=(sigma)/(rhog)` |
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