1.

If \(\rm \frac{{\sin \left( {x\; + \;y} \right)}}{{\sin \left( {x\; - \;y} \right)}} = \frac 53\) then what is \(\rm \frac{{\tan x}}{{\tan y}}\) equal to?1. 22. 43. \(\frac 1 4\)4. \(\frac 12\)

Answer» Correct Answer - Option 2 : 4

Concepts:

If \(\rm \frac A B = \frac C D\), property of componendo and dividendo is given by, \(\rm \frac{A+B}{A-B}=\frac{C+D}{C-D}\)

Formula:

  • sin (x + y) = sin x cos y + cos x sin y
  • sin (x – y) = sin x cos y - cos x sin y

 

Calculation:

Given:

\(\rm \frac{{\sin \left( {x\; + \;y} \right)}}{{\sin \left( {x\; - \;y} \right)}} = \frac 53\)

\(\Rightarrow\rm \;\frac{{\sin x\cos y\; + \;\cos x\sin y}}{{\sin x\cos y\; - \;\cos x\sin y}} = \frac 53\)

Using componendo and dividendo formula, we get

\(\rm \Rightarrow \frac{{(\sin x\cos y + \cos x\sin y) + (\sin x\cos y - \cos x\sin y)}}{{(\sin x\cos y + \cos x\sin y) - (\sin x\cos y - \cos x\sin y)}} = \frac{5+3}{5-3}\)

\(\rm \Rightarrow \;\frac{{2{\rm{\;sin}}x\cos y}}{{2\cos x\sin y}} = \frac{8}{2}\)

\(\rm \therefore \frac{{\tan x}}{{\tan y}} = 4\)


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