If Rolle’s theorem holds for the function f(x)=x3–ax2+bx–4,x∈[ – InterviewSolution

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1.	If Rolle’s theorem holds for the function f(x)=x3–ax2+bx–4,x∈[1,2] with f′(43)=0, then ordered pair (a, b) is equal to :
Answer» If Rolle’s theorem holds for the function $f (x) = x^{3} - a x^{2} + b x - 4, x \in [1, 2]$ with $f^{'} (\frac{4}{3}) = 0,$ then ordered pair (a, b) is equal to :

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