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If roots of quadratic equation x2 – kx + 4 = 0 then k will be(A) 2(B) 1(C) 4(D) 3 |
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Answer» Answer is (C) 4 Given equation x2 – kx + 4 = 0 Comparing it with ax2 + bx + c = 0 We get a = 1, b= -k and c = 4 D = b2 – 4 ac = (-k)2 – 4 × 1 × 4 = k2 – 16 Roots are same D = 0 ⇒ k2 – 16 = 0 ⇒ k2 = 16 ⇒ k = ±√16 ⇒ k = ± 4 |
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