1.

If S=121⋅3+223⋅5+325⋅7+....+10082(2015)⋅(2017) such that 4S=1008+1000+p2000+q, p & q∈I+, then q−p is

Answer»

If S=1213+2235+3257+....+10082(2015)(2017) such that 4S=1008+1000+p2000+q, p & qI+, then qp is



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