If S and T are two sets such that S has 21 elements, T has 32 elements

1.	If S and T are two sets such that S has 21 elements, T has 32 elements and S ∩ T has 11 elements. How many elements does S ∪ T have?
Answer» n(S ∪ T) = n(S) + n(T) – n(S ∩ T) or n(S) = 21 n(T) = 32 n(S ∩ T) = 11 Getting n(S ∪ T) = 21 + 32 – 11 = 42

If S and T are two sets such that S has 21 elements, T has 32 elements and S ∩ T has 11 elements. How many elements does S ∪ T have?

Answer»

n(S ∪ T) = n(S) + n(T) – n(S ∩ T)

or n(S) = 21 n(T) = 32 n(S ∩ T) = 11

Getting n(S ∪ T) = 21 + 32 – 11 = 42

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If S and T are two sets such that S has 21 elements, T has 32 elements and S ∩ T has 11 elements. How many elements does S ∪ T have?

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