If `S and V` are one main scale and one Vernier scale and ` n - 1` divisions on the main scale are equivalent to `n` divisions of the Vernier , thenA. The least count is `S//n`.B. The Vernier constant is `S//n`.C. The same Vernier constant can be used for circular Vernier also.D. The same vernier constant cannot be used for circular Verniers.

If `S and V` are one main scale and one Vernier scale and ` n - 1` div

1.	If `S and V` are one main scale and one Vernier scale and ` n - 1` divisions on the main scale are equivalent to `n` divisions of the Vernier , thenA. The least count is `S//n`.B. The Vernier constant is `S//n`.C. The same Vernier constant can be used for circular Vernier also.D. The same vernier constant cannot be used for circular Verniers.
Answer» Correct Answer - A::B::C Least count ` = 1 MSD - 1 VSD` ` = S - V = S - ((n-1)/( n)) S = ( S)/(n)` `[ because nV = ( n-1) S]` It is also called vernier constant . So choices (a) and (b) are correct. Choice (d) is wrong and choice ( c) is correct , since for all vernier scales similiar approach can be used.

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