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If S is the sample space and P(A) = \(\frac{1}{3}\) P(B) and S = A∪B , where A and B are two mutually exclusive events, then P(A) =A. \(\frac{1}{4}\) B. \(\frac{1}{2}\)C. \(\frac{3}{4}\) D. \(\frac{3}{8}\) |
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Answer» As , S = A ∪ B ∴ P(A ∪ B) = P(S) = 1 As A and B are mutually exclusive events. ∴ P(A ∪ B) = P(A) + P(B) ⇒ 1 = P(A) + 3P(A) [∵ P(A) = 1/3 P(B)] 4P(A) = 1 ∴ P(A) = 1/4 Our answer matches with option (a) ∴ Option (a) is the only correct choice |
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