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If scattering particles are `56` for `90^(@)` angle than this will be at `60^(@)` angleA. 224B. 256C. 98D. 108 |
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Answer» Correct Answer - A Accroding to scattering formula `" " Nprop(1)/(sin^(4)(theta//2))rArr(N_(2))/(N_(1))=[(sin(theta_(1)//2))/(sin(theta_(2)//2))]^(4)` `rArr" " (N_(2))/(N_(1))=[(sin.(90^(@))/(2))/(sin.(60^(@))/(2))]^(4)=[(sin 45^(@))/(sin30^(@))]^(4)` `rArr " " N_(2)=(sqrt(2))^(4)xxN_(1)=4xx56=224` |
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