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| 1. |
If screening does not split the subshell(l) of a given shell(n), how many elements would occur in 5th period.A. 50B. 32C. 18D. 64 |
| Answer» then no of electrons in 5th shell=no. of electron in 5th pd=2xxn^(2)=2xx5^(2)=50` | |