1.

If secθ+tanθ=p , prove that (i) secθ=12(p+1p) (ii) tanθ=12(p−1p) (iii) sinθ=p2−1p2+1

Answer»

If secθ+tanθ=p , prove that

(i) secθ=12(p+1p)

(ii) tanθ=12(p1p)

(iii) sinθ=p21p2+1



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