Saved Bookmarks
| 1. |
If secθ+tanθ=p , prove that (i) secθ=12(p+1p) (ii) tanθ=12(p−1p) (iii) sinθ=p2−1p2+1 |
|
Answer» If secθ+tanθ=p , prove that (i) secθ=12(p+1p) (ii) tanθ=12(p−1p) (iii) sinθ=p2−1p2+1 |
|