1.

If secθ+tanθ=x, then tanθ=(a) x2+1x(b) x2-1x(c) x2+12x(d) x2-12x

Answer» If secθ+tanθ=x, then tanθ=



(a) x2+1x

(b) x2-1x

(c) x2+12x

(d) x2-12x


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