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If set A and B are defined as `A = {(x,y)|y = 1/x, 0 ne x in R}, B = {(x,y)|y = -x , x in R,}`. ThenA. `A cap B=A`B. `A cup B=B`C. `A cup B= phi`D. `A cup B-A` |
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Answer» Correct Answer - C For `A cap B`, We have `-x=1/x` `rArr -x^2 = 1 ` `rArr x^ 2 =-1 ` which is not possible `therefore A cap B = phi ` |
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