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If side length of cube changing at `0.1mm//sec`. Then what will be rate of change of volume, when side length is 2 meterA. `8xx10^(-4)m^(3)//sec`B. `4xx10^(-3)m^(3)//sec`C. `12xx10^(-4)m^(3)//sec`D. `12xx10^(-3)m^(3)//sec` |
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Answer» Correct Answer - C `v=l^(3)` `(dv)/(dt)=3l^(2)((dl)/(dt))` `((dv)/(dt))=3(2)^(2)(10^(-4)m^(3)//sec)` `((dv)/(dt))=12xx10^(-4)m//sec` |
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