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If side length of square changing with time `0.002 m//s` then what will be rate fo change of Area of square when side length become 5m.A. `0.05 m^(2)//s`B. `0.02 m^(2)//sec`C. `0.01 m^(2)//sec`D. `0.03m^(2)//sec` |
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Answer» Correct Answer - B `A=l^(2)` `(dA)/(dt)=2l((dl)/(dt))=2(5)(2xx10^(-3))=2xx10^(-2)m^(2)//sec` `(dA)/(dt)=0.02 m^(2)//sec` |
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