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If sin-1 x + sin-1 y + sin-1 z = 3π/2, the value of x2017 + y2018 + z2019 – 9/(x101 + y101 + z101 is …(a) 0 (b) 1(c) 2 (d) 3 |
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Answer» (a) 0 The maximum value of sin-1 x is π/2 and sin-1 1 = π/2 Here it is given that sin-1 x + sin-1 y + sin-1 z = 3π/2 ⇒ x = y = z = 1 and so 1 + 1 + 1 – 9/(1 + 1+ 1) = 3 - 3 = 0 |
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