If sin (A + B) = 1 and cos (A – B) = 1, 0 ≤ (A + B) ≤ 90 and A – InterviewSolution

1.

If sin (A + B) = 1 and cos (A – B) = 1, 0 ≤ (A + B) ≤ 90 and A > B, then find A and B

Answer»

Here, sin (A + B) = 1

⇒ sin (A + B) = 90 [∵ sin 90 = 1]

⇒ (A + B) = 90 …….(i)

Also, cos (A – B) = 1

⇒ cos (A – B) = 0 [∵ cos 0 = 1]

⇒ A – B = 0 ….(ii)

Solving (i) and (ii), we get:

A = 45 and B = 45

Discussion

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