1.

If sin alpha+sinbeta=l, cos alpha cos beta= m and tan(alpha/2)tan(beta/2)=n(!= 1), then

Answer»

`COS(alpha-beta)=(l^(2)+m^(2)-2)/(2)`
`cos(alpha+beta)=(m^(2)-l^(2))/(m^(2)+l^(2))`
`(1+n)/(1-n)=(l^(2)+m^(2))/(2N)`
`alpha+beta=pi/2` if `l=m`

Answer :A::B::C::D


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