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If sin x = 1/√5 , sin y = 1/√10 , where 0 < x < π/2, 0 < y < π/2, then what is (x + y) equal to? a. π b. π/2 c. π/4 d. 0 |
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Answer» Correct option c. π/4 Explanation: sinx = 1/√5, siny = 1/√10 sin (x + y) = sinx . cosy + cosx siny cosx = √(1 - 1/5) = 2/√5, cosy = √(1 - 1/10) = √(9/10) = 3/√10 sin(x +y) = 1/√5 x 3/√10 + 2/√5 x 1/√10 = 5/√50 = 1/√2 ⇒ x + y = 45° |
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