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The angle between the two lines lx + my + n = 0 and l’x + m’y + n’ = 0 is given by tan–1θ . What θ equal to?a. |(lm' - l'm)/(ll' - mm')|b. |(lm' + l'm)/(ll' + mm')|c. |(lm' - l'm)/(ll' + mm')|d. |(lm' + l'm)/(ll' - mm')| |
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Answer» Correct option c. |(lm' - l'm)/(ll' + mm')| Explanation: tan–1θ = tan–1|(lm' - l'm)/(ll' + mm')| ⇒ θ = |(lm' - l'm)/(ll' + mm')| |
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