1.

If sin x = 12/13 and lies in the second quadrant, find the value of sec x + tan x.

Answer»

Given as 

sin x = 12/13 and x lies in the second quadrant.

As we know, in second quadrant, sin x and cosec x are positive and all other ratios are negative.

On using the formulas,

cos x = √(1 - sin2 x)

= – √(1 - (12/13)2)

= – √(1 - (144/169))

= – √(169 - 144)/169

= -√(25/169)

= – 5/13

As we know,

tan x = sin x/cos x

sec x = 1/cos x

Then,

tan x = (12/13)/(-5/13)

= -12/5

sec x = 1/(-5/13)

= -13/5

sec x + tan x = -13/5 + (-12/5)

= (-13 - 12)/5

= -25/5

= -5

Thus, sec x + tan x = -5



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