1.

If ∫sin2xcos2x dx=xA+1Bsin4x+C, then the value of A−B is equal to(where A,B are fixed constants and C is integration constant)

Answer» If sin2xcos2x dx=xA+1Bsin4x+C, then the value of AB is equal to

(where A,B are fixed constants and C is integration constant)


Discussion

No Comment Found