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If ∫sin2xcos2x dx=xA+1Bsin4x+C, then the value of A−B is equal to(where A,B are fixed constants and C is integration constant) |
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Answer» If ∫sin2xcos2x dx=xA+1Bsin4x+C, then the value of A−B is equal to (where A,B are fixed constants and C is integration constant) |
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