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If sinA+sinB=a and cosA+cosB=b, show that cos(A+B) = (b^2-a^2)/(b^2+a^2) |
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Answer» SOLUTION :COS(A+B) =(1-tan^2((A+B)/2)/(1+tan^2((A+B)/2) = (1-a^2/b^2)/(1+a^2/b^2) = (b^2-a^2)/(b^2+a^2)` |
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