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If sinθ=1213,0∘<θ<90∘, find the value of : sin2θ−cos2θ2sinθ.cosθ×1tan2θ

Answer» If sinθ=1213,0∘<θ<90∘, find the value of :
sin2θ−cos2θ2sinθ.cosθ×1tan2θ


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