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If sinθ = cos(θ – 45°), where θ is acute, find the value of θ. |
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Answer» We have, sinθ = cos(θ – 45°), Where θ is acute angle. ⇒ cos(90° − θ) = cos(θ − 45°) (∵ cos(90° − θ) = sinθ) ⇒ 90° − θ = θ − 45° ⇒ 2θ = 90° + 45° = 135° ⇒ θ = \(\frac{135°}{2}\) = 62.5°. Hence, The value of θ is 62.5°. |
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