If sinθ1sinθ2−cosθ1cosθ2−1=0, where θ1+θ2∈(0,2π), then th – InterviewSolution

1.	If sinθ1sinθ2−cosθ1cosθ2−1=0, where θ1+θ2∈(0,2π), then the value of (1+tanθ14)(1+tanθ24) is
Answer» If $sin θ_{1} sin θ_{2} - cos θ_{1} cos θ_{2} - 1 = 0,$ where $θ_{1} + θ_{2} \in (0, 2 π),$ then the value of $(1 + tan \frac{θ_{1}}{4}) (1 + tan \frac{θ_{2}}{4})$ is

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