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If `sintheta=-1/2` and `tantheta=1/sqrt(3)` then `theta` is equal to,A. `30^(@)`B. `150^(@)`C. `210^(@)`D. none of these |
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Answer» Let us first find out `theta` lying between 0 and `360^(@)`. Since `sintheta=-1/2 rArr theta=210^(@)` or `330^(@)` and `tantheta=1/sqrt(3) rArr theta=30^(@)` or `210^(@)` Hence, `theta=210^(@)` or `(7pi)/6` is the value satisfying both. |
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