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If `sintheta=1/2a n dcostheta=-(sqrt(3))/2,`then the general value of `theta`is `(n in Z)dot`A. `2n pi+(5pi)/6`B. `2n pi+pi/6`C. `2n pi+(7pi)/6`D. `2npi+pi/4` |
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Answer» Correct Answer - A `sin theta=1//2` and `cos theta=-sqrt(3)//2` `rArr theta` lies in the second quadrant. `rArr sin theta=sin 5pi//6`, `:. Theta=2npi+(5pi//6), n in Z` |
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