InterviewSolution
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InterviewSolution
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If `sintheta +cos theta =m` and `sec theta + cosec theta =n` then `n(m+1)(m-1)` equals |
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Answer» Here, `sintheta+costheta = m` `sectheta+cosectheta = n` `:. n(m+1)(m-1) = n(m^2-1)` `= (sectheta+cosectheta)((sintheta+costheta)^2-1)` `= (1/costheta+1/sintheta)(sin^2theta+cos^2theta+2sinthetacostheta-1)` `= ((sin theta+costheta)/(sinthetacostheta))(1+2sinthetacostheta-1)` `=(2(sintheta+costheta)sinthetacostheta)/(sinthetacostheta)` `=(2(sintheta+costheta)` `=2m` `:. n(m+1)(m-1) = 2m` |
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