If sintheta=(m^(2)-n^(2))/(m^(2)+n^(2)), then tantheta=? – InterviewSolution

InterviewSolution

1.	If sintheta=(m^(2)-n^(2))/(m^(2)+n^(2)), then tantheta=?
Answer» `(m^(2)+N^(2))/(2MN)` `(m^(2)-n^(2))/(2mn)` `(m^(2)+n^(2))/(m^(2)-n^(2))` `(m^(2)-n^(2))/(m^(2)+n^(2))` ANSWER :B

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