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If sinθsin2(π8+θ2)−sin2(π8−θ2)=k (θ≠2nπ), then value of 2k2 is |
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Answer» If sinθsin2(π8+θ2)−sin2(π8−θ2)=k (θ≠2nπ), then value of 2k2 is |
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